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For T< 553 K: v x 10s = U8 - 2.0 x 10"3T + 3.42 xl^T2 h = 130 + 4.99(T - 293) - 2.95 x lO-^T1 - 2931)

+ 3.1 x ](W3- 2933) s = 0.28 + 4.9907293) - 5.9 x HH(T - 293) + 4.7 x lO^fF - 293J)

Note: The last row in each table gives saturation values.

Example: The coefficient of compressibility at 240°C (513 K) between 5 and 10 MPa is determined from the numerical entries in the 5 MPa and 10 MPa subtables:

Because v x 103 is given to only three significant figures, the above value of 0 is not very accurate. Using values from the tabulation in Reference 5, P = 1.3 x 10~3.

Example: The heal capacity at constant pressure of liquid water at 5 MPa between 220°C (493 K) and 100°C (513 K) is obtained by the approximating the derivative dh/dT by:

This value of CF is equivalent to 1 cal/g-°C. The calorie unit is the quantity of heat needed to raise the temperature of 1 gram of water by 1 degree Celsius.

The single-phase tables often require double interpolation, an example of which is given below.

Example: The enthalpy of steam at 230°C (503 K) and 240 kPa is determined in two steps:

Step 1: Interpolate on 503 K at bounding pressures:

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