First, the mixture is cooled from T2 to T3 without condensation. The heat effect of this step is removal of sensible heat. Second, the required quantity of water is condensed at temperature T3, during which the enthalpy of vaporization is released. From Eq (5.10): Ahvap = 5300 x 8.314 = 44,000 J/mole and:
Q23 = H2 -H3 = ntotCp(T2 - T3) + f (nv2/na)Ahvap = 725 + 1425 = 2150 J/mole air
Problems 8.2, 8.12, 8.13, 8.15, and 8.21 explore other aspects of the above condensation process.
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